3.689 \(\int \frac{(f+g x)^4 (a d e+(c d^2+a e^2) x+c d e x^2)^{3/2}}{(d+e x)^{3/2}} \, dx\)

Optimal. Leaf size=336 \[ \frac{16 (f+g x)^3 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{32 (f+g x)^2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^2}{429 c^3 d^3 (d+e x)^{5/2}}+\frac{128 g \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^3}{3003 c^4 d^4 e (d+e x)^{3/2}}-\frac{128 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^3 \left (2 a e^2 g-c d (7 e f-5 d g)\right )}{15015 c^5 d^5 e (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}} \]

[Out]

(-128*(c*d*f - a*e*g)^3*(2*a*e^2*g - c*d*(7*e*f - 5*d*g))*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(1501
5*c^5*d^5*e*(d + e*x)^(5/2)) + (128*g*(c*d*f - a*e*g)^3*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(3003*c
^4*d^4*e*(d + e*x)^(3/2)) + (32*(c*d*f - a*e*g)^2*(f + g*x)^2*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(
429*c^3*d^3*(d + e*x)^(5/2)) + (16*(c*d*f - a*e*g)*(f + g*x)^3*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/
(143*c^2*d^2*(d + e*x)^(5/2)) + (2*(f + g*x)^4*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(13*c*d*(d + e*x
)^(5/2))

________________________________________________________________________________________

Rubi [A]  time = 0.606542, antiderivative size = 336, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 46, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.065, Rules used = {870, 794, 648} \[ \frac{16 (f+g x)^3 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{32 (f+g x)^2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^2}{429 c^3 d^3 (d+e x)^{5/2}}+\frac{128 g \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^3}{3003 c^4 d^4 e (d+e x)^{3/2}}-\frac{128 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2} (c d f-a e g)^3 \left (2 a e^2 g-c d (7 e f-5 d g)\right )}{15015 c^5 d^5 e (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}} \]

Antiderivative was successfully verified.

[In]

Int[((f + g*x)^4*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(d + e*x)^(3/2),x]

[Out]

(-128*(c*d*f - a*e*g)^3*(2*a*e^2*g - c*d*(7*e*f - 5*d*g))*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(1501
5*c^5*d^5*e*(d + e*x)^(5/2)) + (128*g*(c*d*f - a*e*g)^3*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(3003*c
^4*d^4*e*(d + e*x)^(3/2)) + (32*(c*d*f - a*e*g)^2*(f + g*x)^2*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(
429*c^3*d^3*(d + e*x)^(5/2)) + (16*(c*d*f - a*e*g)*(f + g*x)^3*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/
(143*c^2*d^2*(d + e*x)^(5/2)) + (2*(f + g*x)^4*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2))/(13*c*d*(d + e*x
)^(5/2))

Rule 870

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :>
-Simp[(e*(d + e*x)^(m - 1)*(f + g*x)^n*(a + b*x + c*x^2)^(p + 1))/(c*(m - n - 1)), x] - Dist[(n*(c*e*f + c*d*g
 - b*e*g))/(c*e*(m - n - 1)), Int[(d + e*x)^m*(f + g*x)^(n - 1)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c,
 d, e, f, g, m, p}, x] && NeQ[e*f - d*g, 0] && NeQ[b^2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !Integ
erQ[p] && EqQ[m + p, 0] && GtQ[n, 0] && NeQ[m - n - 1, 0] && (IntegerQ[2*p] || IntegerQ[n])

Rule 794

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp
[(g*(d + e*x)^m*(a + b*x + c*x^2)^(p + 1))/(c*(m + 2*p + 2)), x] + Dist[(m*(g*(c*d - b*e) + c*e*f) + e*(p + 1)
*(2*c*f - b*g))/(c*e*(m + 2*p + 2)), Int[(d + e*x)^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g
, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[m + 2*p + 2, 0] && (NeQ[m, 2] || Eq
Q[d, 0])

Rule 648

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1)
*(a + b*x + c*x^2)^(p + 1))/(c*(p + 1)), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ[c
*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + p, 0]

Rubi steps

\begin{align*} \int \frac{(f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{(d+e x)^{3/2}} \, dx &=\frac{2 (f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}}+\frac{(8 (c d f-a e g)) \int \frac{(f+g x)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{(d+e x)^{3/2}} \, dx}{13 c d}\\ &=\frac{16 (c d f-a e g) (f+g x)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}}+\frac{\left (48 (c d f-a e g)^2\right ) \int \frac{(f+g x)^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{(d+e x)^{3/2}} \, dx}{143 c^2 d^2}\\ &=\frac{32 (c d f-a e g)^2 (f+g x)^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{429 c^3 d^3 (d+e x)^{5/2}}+\frac{16 (c d f-a e g) (f+g x)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}}+\frac{\left (64 (c d f-a e g)^3\right ) \int \frac{(f+g x) \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{(d+e x)^{3/2}} \, dx}{429 c^3 d^3}\\ &=\frac{128 g (c d f-a e g)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{3003 c^4 d^4 e (d+e x)^{3/2}}+\frac{32 (c d f-a e g)^2 (f+g x)^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{429 c^3 d^3 (d+e x)^{5/2}}+\frac{16 (c d f-a e g) (f+g x)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}}+\frac{\left (64 (c d f-a e g)^3 \left (7 f-\frac{5 d g}{e}-\frac{2 a e g}{c d}\right )\right ) \int \frac{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}{(d+e x)^{3/2}} \, dx}{3003 c^3 d^3}\\ &=\frac{128 (c d f-a e g)^3 \left (7 f-\frac{5 d g}{e}-\frac{2 a e g}{c d}\right ) \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{15015 c^4 d^4 (d+e x)^{5/2}}+\frac{128 g (c d f-a e g)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{3003 c^4 d^4 e (d+e x)^{3/2}}+\frac{32 (c d f-a e g)^2 (f+g x)^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{429 c^3 d^3 (d+e x)^{5/2}}+\frac{16 (c d f-a e g) (f+g x)^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{143 c^2 d^2 (d+e x)^{5/2}}+\frac{2 (f+g x)^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}}{13 c d (d+e x)^{5/2}}\\ \end{align*}

Mathematica [A]  time = 0.245682, size = 195, normalized size = 0.58 \[ \frac{2 ((d+e x) (a e+c d x))^{5/2} \left (16 a^2 c^2 d^2 e^2 g^2 \left (143 f^2+130 f g x+35 g^2 x^2\right )-64 a^3 c d e^3 g^3 (13 f+5 g x)+128 a^4 e^4 g^4-8 a c^3 d^3 e g \left (715 f^2 g x+429 f^3+455 f g^2 x^2+105 g^3 x^3\right )+c^4 d^4 \left (10010 f^2 g^2 x^2+8580 f^3 g x+3003 f^4+5460 f g^3 x^3+1155 g^4 x^4\right )\right )}{15015 c^5 d^5 (d+e x)^{5/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[((f + g*x)^4*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2))/(d + e*x)^(3/2),x]

[Out]

(2*((a*e + c*d*x)*(d + e*x))^(5/2)*(128*a^4*e^4*g^4 - 64*a^3*c*d*e^3*g^3*(13*f + 5*g*x) + 16*a^2*c^2*d^2*e^2*g
^2*(143*f^2 + 130*f*g*x + 35*g^2*x^2) - 8*a*c^3*d^3*e*g*(429*f^3 + 715*f^2*g*x + 455*f*g^2*x^2 + 105*g^3*x^3)
+ c^4*d^4*(3003*f^4 + 8580*f^3*g*x + 10010*f^2*g^2*x^2 + 5460*f*g^3*x^3 + 1155*g^4*x^4)))/(15015*c^5*d^5*(d +
e*x)^(5/2))

________________________________________________________________________________________

Maple [A]  time = 0.054, size = 283, normalized size = 0.8 \begin{align*}{\frac{ \left ( 2\,cdx+2\,ae \right ) \left ( 1155\,{g}^{4}{x}^{4}{c}^{4}{d}^{4}-840\,a{c}^{3}{d}^{3}e{g}^{4}{x}^{3}+5460\,{c}^{4}{d}^{4}f{g}^{3}{x}^{3}+560\,{a}^{2}{c}^{2}{d}^{2}{e}^{2}{g}^{4}{x}^{2}-3640\,a{c}^{3}{d}^{3}ef{g}^{3}{x}^{2}+10010\,{c}^{4}{d}^{4}{f}^{2}{g}^{2}{x}^{2}-320\,{a}^{3}cd{e}^{3}{g}^{4}x+2080\,{a}^{2}{c}^{2}{d}^{2}{e}^{2}f{g}^{3}x-5720\,a{c}^{3}{d}^{3}e{f}^{2}{g}^{2}x+8580\,{c}^{4}{d}^{4}{f}^{3}gx+128\,{a}^{4}{e}^{4}{g}^{4}-832\,{a}^{3}cd{e}^{3}f{g}^{3}+2288\,{a}^{2}{c}^{2}{d}^{2}{e}^{2}{f}^{2}{g}^{2}-3432\,a{c}^{3}{d}^{3}e{f}^{3}g+3003\,{f}^{4}{c}^{4}{d}^{4} \right ) }{15015\,{c}^{5}{d}^{5}} \left ( cde{x}^{2}+a{e}^{2}x+c{d}^{2}x+ade \right ) ^{{\frac{3}{2}}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((g*x+f)^4*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2)/(e*x+d)^(3/2),x)

[Out]

2/15015*(c*d*x+a*e)*(1155*c^4*d^4*g^4*x^4-840*a*c^3*d^3*e*g^4*x^3+5460*c^4*d^4*f*g^3*x^3+560*a^2*c^2*d^2*e^2*g
^4*x^2-3640*a*c^3*d^3*e*f*g^3*x^2+10010*c^4*d^4*f^2*g^2*x^2-320*a^3*c*d*e^3*g^4*x+2080*a^2*c^2*d^2*e^2*f*g^3*x
-5720*a*c^3*d^3*e*f^2*g^2*x+8580*c^4*d^4*f^3*g*x+128*a^4*e^4*g^4-832*a^3*c*d*e^3*f*g^3+2288*a^2*c^2*d^2*e^2*f^
2*g^2-3432*a*c^3*d^3*e*f^3*g+3003*c^4*d^4*f^4)*(c*d*e*x^2+a*e^2*x+c*d^2*x+a*d*e)^(3/2)/c^5/d^5/(e*x+d)^(3/2)

________________________________________________________________________________________

Maxima [A]  time = 1.30834, size = 558, normalized size = 1.66 \begin{align*} \frac{2 \,{\left (c^{2} d^{2} x^{2} + 2 \, a c d e x + a^{2} e^{2}\right )} \sqrt{c d x + a e} f^{4}}{5 \, c d} + \frac{8 \,{\left (5 \, c^{3} d^{3} x^{3} + 8 \, a c^{2} d^{2} e x^{2} + a^{2} c d e^{2} x - 2 \, a^{3} e^{3}\right )} \sqrt{c d x + a e} f^{3} g}{35 \, c^{2} d^{2}} + \frac{4 \,{\left (35 \, c^{4} d^{4} x^{4} + 50 \, a c^{3} d^{3} e x^{3} + 3 \, a^{2} c^{2} d^{2} e^{2} x^{2} - 4 \, a^{3} c d e^{3} x + 8 \, a^{4} e^{4}\right )} \sqrt{c d x + a e} f^{2} g^{2}}{105 \, c^{3} d^{3}} + \frac{8 \,{\left (105 \, c^{5} d^{5} x^{5} + 140 \, a c^{4} d^{4} e x^{4} + 5 \, a^{2} c^{3} d^{3} e^{2} x^{3} - 6 \, a^{3} c^{2} d^{2} e^{3} x^{2} + 8 \, a^{4} c d e^{4} x - 16 \, a^{5} e^{5}\right )} \sqrt{c d x + a e} f g^{3}}{1155 \, c^{4} d^{4}} + \frac{2 \,{\left (1155 \, c^{6} d^{6} x^{6} + 1470 \, a c^{5} d^{5} e x^{5} + 35 \, a^{2} c^{4} d^{4} e^{2} x^{4} - 40 \, a^{3} c^{3} d^{3} e^{3} x^{3} + 48 \, a^{4} c^{2} d^{2} e^{4} x^{2} - 64 \, a^{5} c d e^{5} x + 128 \, a^{6} e^{6}\right )} \sqrt{c d x + a e} g^{4}}{15015 \, c^{5} d^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^4*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2)/(e*x+d)^(3/2),x, algorithm="maxima")

[Out]

2/5*(c^2*d^2*x^2 + 2*a*c*d*e*x + a^2*e^2)*sqrt(c*d*x + a*e)*f^4/(c*d) + 8/35*(5*c^3*d^3*x^3 + 8*a*c^2*d^2*e*x^
2 + a^2*c*d*e^2*x - 2*a^3*e^3)*sqrt(c*d*x + a*e)*f^3*g/(c^2*d^2) + 4/105*(35*c^4*d^4*x^4 + 50*a*c^3*d^3*e*x^3
+ 3*a^2*c^2*d^2*e^2*x^2 - 4*a^3*c*d*e^3*x + 8*a^4*e^4)*sqrt(c*d*x + a*e)*f^2*g^2/(c^3*d^3) + 8/1155*(105*c^5*d
^5*x^5 + 140*a*c^4*d^4*e*x^4 + 5*a^2*c^3*d^3*e^2*x^3 - 6*a^3*c^2*d^2*e^3*x^2 + 8*a^4*c*d*e^4*x - 16*a^5*e^5)*s
qrt(c*d*x + a*e)*f*g^3/(c^4*d^4) + 2/15015*(1155*c^6*d^6*x^6 + 1470*a*c^5*d^5*e*x^5 + 35*a^2*c^4*d^4*e^2*x^4 -
 40*a^3*c^3*d^3*e^3*x^3 + 48*a^4*c^2*d^2*e^4*x^2 - 64*a^5*c*d*e^5*x + 128*a^6*e^6)*sqrt(c*d*x + a*e)*g^4/(c^5*
d^5)

________________________________________________________________________________________

Fricas [A]  time = 1.6907, size = 1007, normalized size = 3. \begin{align*} \frac{2 \,{\left (1155 \, c^{6} d^{6} g^{4} x^{6} + 3003 \, a^{2} c^{4} d^{4} e^{2} f^{4} - 3432 \, a^{3} c^{3} d^{3} e^{3} f^{3} g + 2288 \, a^{4} c^{2} d^{2} e^{4} f^{2} g^{2} - 832 \, a^{5} c d e^{5} f g^{3} + 128 \, a^{6} e^{6} g^{4} + 210 \,{\left (26 \, c^{6} d^{6} f g^{3} + 7 \, a c^{5} d^{5} e g^{4}\right )} x^{5} + 35 \,{\left (286 \, c^{6} d^{6} f^{2} g^{2} + 208 \, a c^{5} d^{5} e f g^{3} + a^{2} c^{4} d^{4} e^{2} g^{4}\right )} x^{4} + 20 \,{\left (429 \, c^{6} d^{6} f^{3} g + 715 \, a c^{5} d^{5} e f^{2} g^{2} + 13 \, a^{2} c^{4} d^{4} e^{2} f g^{3} - 2 \, a^{3} c^{3} d^{3} e^{3} g^{4}\right )} x^{3} + 3 \,{\left (1001 \, c^{6} d^{6} f^{4} + 4576 \, a c^{5} d^{5} e f^{3} g + 286 \, a^{2} c^{4} d^{4} e^{2} f^{2} g^{2} - 104 \, a^{3} c^{3} d^{3} e^{3} f g^{3} + 16 \, a^{4} c^{2} d^{2} e^{4} g^{4}\right )} x^{2} + 2 \,{\left (3003 \, a c^{5} d^{5} e f^{4} + 858 \, a^{2} c^{4} d^{4} e^{2} f^{3} g - 572 \, a^{3} c^{3} d^{3} e^{3} f^{2} g^{2} + 208 \, a^{4} c^{2} d^{2} e^{4} f g^{3} - 32 \, a^{5} c d e^{5} g^{4}\right )} x\right )} \sqrt{c d e x^{2} + a d e +{\left (c d^{2} + a e^{2}\right )} x} \sqrt{e x + d}}{15015 \,{\left (c^{5} d^{5} e x + c^{5} d^{6}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^4*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2)/(e*x+d)^(3/2),x, algorithm="fricas")

[Out]

2/15015*(1155*c^6*d^6*g^4*x^6 + 3003*a^2*c^4*d^4*e^2*f^4 - 3432*a^3*c^3*d^3*e^3*f^3*g + 2288*a^4*c^2*d^2*e^4*f
^2*g^2 - 832*a^5*c*d*e^5*f*g^3 + 128*a^6*e^6*g^4 + 210*(26*c^6*d^6*f*g^3 + 7*a*c^5*d^5*e*g^4)*x^5 + 35*(286*c^
6*d^6*f^2*g^2 + 208*a*c^5*d^5*e*f*g^3 + a^2*c^4*d^4*e^2*g^4)*x^4 + 20*(429*c^6*d^6*f^3*g + 715*a*c^5*d^5*e*f^2
*g^2 + 13*a^2*c^4*d^4*e^2*f*g^3 - 2*a^3*c^3*d^3*e^3*g^4)*x^3 + 3*(1001*c^6*d^6*f^4 + 4576*a*c^5*d^5*e*f^3*g +
286*a^2*c^4*d^4*e^2*f^2*g^2 - 104*a^3*c^3*d^3*e^3*f*g^3 + 16*a^4*c^2*d^2*e^4*g^4)*x^2 + 2*(3003*a*c^5*d^5*e*f^
4 + 858*a^2*c^4*d^4*e^2*f^3*g - 572*a^3*c^3*d^3*e^3*f^2*g^2 + 208*a^4*c^2*d^2*e^4*f*g^3 - 32*a^5*c*d*e^5*g^4)*
x)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*sqrt(e*x + d)/(c^5*d^5*e*x + c^5*d^6)

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)**4*(a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(3/2)/(e*x+d)**(3/2),x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^4*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2)/(e*x+d)^(3/2),x, algorithm="giac")

[Out]

Timed out